Blog Mathematics (Lessons, class hours)

Extracurricular: "Journey to a Fairy Tale"

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Shangina Irina Evgenievna
math teacher
GBOU SECONDARY SCHOOL NO. 11
named after Hero of the Soviet Union Aipov M.I.
g.o. Oktyabrsk, Samara region.

Class Purpose: increase students' knowledge of addition and subtraction of fractions.

Tasks:
(a) educational:

  • To foster respect for one another, mutual understanding, self-confidence;
  • To contribute to the development of students' desire and need to study mathematics.

(b) developmental:

  • Development of intelligence, will, emotions;
  • Speech development;
  • Development of hard work and independence in solving problems.

(c) educational:

  • Continue building skills to perform actions on fractions;
  • Repeat the methods of solving simple problems by percentages.

Equipment: chalk; board; pen, sheets for solving tasks; cards with tasks; visibility that contributes to the lesson (Baba Yaga's hut, the Puss's carriage in boots, the houses of Malvina and Old Man Hottabych).

Class progress

Teacher. Hello guys. Today we're going to make a fascinating journey. I got hold of a letter from Old Man Hottabych in which he offers to make a journey into the Realm of Fairy Tales.
'Dear guys!
Today I invite everyone who loves fairy tale and mathematics to take an exciting journey You will find encounters with fairy tale characters There will of course be difficulties and obstacles on the way that you must overcome I send for you a carpet plane that can only rise if you solve the problem: Carpet speed plane 10.58 km/h Round this number to ones I wish you a pleasant journey I look forward to meeting you.
Old Man Hottabych

Teacher. Guys, let's do the problem and continue the journey.
Problem solution.
10,58 km/h 11 km/h.

Teacher. The landing on the magic carpet is over. We're flying to the Fairy Tale Realm. Below us is the far-ninth realm, the thirtiest state. The flying carpet goes down and we enter the fairy land.
You have a long road ahead through the Realm of Fairy Tales, the length of this road you will learn by solving the following problem.
The road consists of four sections, the first section is 4.35 km long, the second is 5.75 km, the third is 6.95 km, the fourth is 2.8 km Find the length of the road and round the value to units, to hundredths.
Problem solution. 1) 4.35 + 5.75 + 6.95 + 2.8 = 19.85 (km) length of the entire road.
2) 19.85 km 20 km.
3) 19.85 km 19.9 km.
Answer: 19.85 km.
Teacher. On the road! But what is it? It's Baba's house - Yagi.
Baba - Yaga. Babes, help me, unlock the door! I quarreled with Koschey the Immortal and he closed the door - no witchcraft helps open it And he said that the door itself would open if you find the root of equation 16.5 - (x + 3.4) = 4.9. The word "root" I know there are so many roots I dried for the winter and what kind of sophisticated word "equation" - I haven’t heard. Help, don’t leave the old lady in trouble.
Teacher. Let's solve the equation, let's help Baba Yaga, guys.

Solving equation

16.5 - (x + 3.4) = 4.9
x + 3.4 = 16.5 - 4.9
x + 3.4 = 11.6
x = 11.6 is 3.4
x = 8.2.
Answer: x = 8.2.

Baba - Yaga. Thank you guys, hold the ball - it will help you meet other fairy-tale characters.
Teacher. We continue on. But what do I see? The road was blocked for us by a river and the bridge is not visible. What should we do?
Apprentice. Look, something is written here:
"If you help a boatman know the speed of his boat, he will transport you to the other side, 1.7 km/h river flow speed, 3.8 km/h boat speed against river flow, What is the speed of the boat?"

Problem solution.
1) 3.8 + 1.7 = 5.5 (km/h) boat speed.
Answer: 5.5 km/h.

Teacher. We got across the river in time because I see a carriage in which a Puss in Boots is traveling.
Pupils. Hello, Puss in Boots Give us a ride in your carriage.
Cat in boots. Hello guys.I'd give you a ride. But the mowers asked me to help them solve the problem, and until I solve it, the carriage will move. If you help me, I'll complete the task faster and head on.
Teacher. Well, guys, let's help the Puss in Boots solve the problem?
Pupils. Let's help.
Puss in Boots. Then listen to the task.
On the first day, mowers mowed down a wheat field of 18.37 hectares, 5.7 hectares more than on the second day and 2.21 hectares more than on the third day. What area field did the mowers mow in three days?

{module Yandex}

Problem solution.
1) 18.37 - 5.7 = 12.67 (ha) mowed on the second day.
2) 18.37 - 2.21 = 16.16 (ha) mowed on day three.
3) 18.37 + 12.67 + 16.16 = 47.2 (ha) mowed in three days.

Answer: 47.2 hectares.

Puss in Boots.Thank you guys Sit down I'll give you a ride.
Teacher Look, guys, who is sitting so sad?
Pupils. This is Pinocchio! Who upset you so much, Pinocchio?
Pinocchio. Malvina! Very smart! She solves some examples herself all day and forces me, and even threatens to leave me without lunch! Help me cope with the task.
Pupils. Of course we will help.
decision

Teacher. Back on the road! I see the lodge. Let's go into it. Look carefully. In the far corner of the room sits our friend Old Man Hottabych. But what is it? He's upset about something.
Old Hottabych.O woe to me! The mice climbed into the closet with my manuscripts and ruined them terribly. I'm suffering, suffering, but not how I can't restore them. Help, guys!
Insert instead of * missing digits.

{module Google_kvadrat}

Old Hottabych. Thank you guys! now try guessing mine to call it "profession" with the clue key (assignment responses) 30.4 - "and" 72 - "n" 385 - "e", 6.67 - "j"
Assignments.

  • Round to units: 384,952.
  • Solve the equation: x + 16.23 - 15.8 = 7.1.
  • Calculate: 50 - 22.84 + 3.24.
  • Solve the equation: x : 9 = 8.

(Having completed all tasks, students add the word - Gin from letters)

Teacher. We figured out what "profession" Old Man Hottabych has. But to go back we need to solve another problem.
The team was instructed to repair a 760 m long section of the road. How many meters of road will they repair when they complete 30% of the task, 50% of the task, 10% of the task?
Problem solution.
1) 760 : 100 = 7.6 (m) 1%
2) 7.6 × 30 = 228 (m) 30%
3) 7.6 × 50 = 380 (m) 50%
4) 7.6 × 10 = 76 (m) 10%

Answer: 228 m, 380 m, 76 m.

Teacher. We finished our journey through the fairytale land Did you enjoy our journey?
Pupils. Liked.
Teacher. What useful things did you do in this lesson?
Pupils. We repeated rounding numbers, solving problems by percentages, and helped many fairy-tale characters cope with difficult situations.
Teacher. Well done guys. Our class is over.

{module Yandex}

Sports Equipment Crossword
Scenario for the festive concert for March 8th

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